答案：解：根据正奇数排列的正三角图表知，2009是第1005个奇数，应

答案：解：根据正奇数排列的正三角图表知，2009是第1005个奇数，应排在i行（其中i∈N*），
则1+2+3+…+（i-1）=
i(i-1)
2
＜1005①，且1+2+3+…+i=
i(i+1)
2
＞1005②；
验证i=45时，①②式成立，所以i=45；
第45行第1个奇数是2×
44×45
2
+1=1981，而1981+2（j-1）=2009，∴j=15；
所以，2009在第45行第15个数，则i+j=60；
故答案为：60．

Kết quả (Anh) 1:

Answer: solutions: regular triangle based on the odd-numbered chart knowing, 2009 is the 1005th odd, should be top row (I ∈ N*),1+2+3+...+ (i-1) =i(i-1)2<1005, and 1+2+3+...+i=i(i+1)2>1005②;When validating i=45 ① ② establishment, so i=45;45th row 1th odd 2x44x452+1=1981, 1981+2 (j-1) = 2009 ∴ j=15;Therefore, the 15th 2009 at 45th row number is i+j=60;So the answer is: 60.

Kết quả (Anh) 2:

The answer: Solution: According to the Triangle chart positive odd arrangement know, 2009 is the first odd 1005, should be ranked in the i-th row (where i∈N *),
then + 2 + 3 + 1 ... + (i-1) =
i (i-1)
2
<1005①, and 1 + 2 + 3 + ... + i =
i (i + 1)
2
> 1005②;
verify i = 45 when, ①② style establishment, so i = 45;
45, line 1 is an odd number × 2
44 × 45
2
+ 1 = 1981, and 1981 + 2 (j-1) = 2009, ∴j = 15;
therefore, in 2009 the number of 15 line 45, the i + j = 60;
therefore, the answer is: 60.

Kết quả (Anh) 3:

Answer: solution: according to known is an odd number of arrayed Triangle Chart, 2009 is the 1005 an odd number, row on row I (where I is the n *),Then 1+2+3+... + (i-1) =I (i-1)Two< 1005, and 1+2+3+... +i=I (i+1)Two> 1005;Verify i=45, the type was established, so i=45;Forty-fifth lines and first odd numbers are 2 *.44 x 45Two+1=1981, 1981+2 (J-1) =2009, j=15 r;So, Fifteenth in the forty-fifth line of the number of 2009, then i+j=60;So the answer is: 60